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SOS National Mathematics in 20 Minutes (First Aid)
1. If the bottom diameter is 15cm, the bottom area is 176.625cm, which is 5cm higher.

The sum of the volumes of & ltbr & gt cylinder and cone is 883. 125 cubic centimeters.

& ltbr & gt Set cone volume x.

& ltbr & gtX+3x = 883.6438+025。

& ltbr & gtX=220.78 125

& ltbr & gt So the cylinder volume is 662.34375 cubic centimeters and the cone is 220.438+025 cubic centimeters.

& ltbr & gt

& ltbr & gt2. The original volume is 3.14 * 5 * 5 *10 *1/3 = 785/3 cubic centimeters.

& ltbr & gt's current volume is 3.14 * 4 * 9 *1/3 = 452.16/3 cubic centimeters.

& ltbr & gt785/3-452. 16/3 is 332.84/3 cubic centimeters.

& ltbr & gt Therefore, the volume of the new cone is reduced by 332.84/3 cubic centimeters compared with the original volume.