Lnx=ht+C(C is an arbitrary constant)
So if we take both sides as e exponents, we will get X = C' E HT and the constant C'≠0.
Don't forget the initial condition x(t=0)=x0, so C'=x0.
The result is x = x0× e (ht).
In short, any equation that can be sorted out, the variables on both sides of the equal sign, can be solved in this way.