dr
So the straight line l is separated from the circle at this time.
Second, the solution: because straight lines and circles have one thing in common.
So the straight line is tangent to the circle.
Then d=r= 10cm.
So the distance from the center of the circle to the straight line is 10cm.
(1) Intersection 2
(2) Tangency 1
(3) Phase separation 0
Solution: Because the diameter of ⊙O is 10 cm.
So r=5cm.
And because the distance from the center O to the straight line AB is 10 cm.
So d= 10cm.
d>r
Then ⊙O is separated from the sub-rows.
It's over. It's over. . . Oh, the third question has the same steps as the first question. Because you fill in the blanks, I have no writing process.
You see, I wrote so much,,,