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Mathematical oil pouring problem
To do this kind of problem, we should find an invariant as "1". Because the bucket is unchanged, it is considered as "1"

Then crude oil accounts for 1/(8%) = 25/2 barrels, and late oil accounts for 1/2 barrels.

The barrel weight is 48/(25/2- 1/2) = 4 (kg).

So crude oil 4/(8%) = 50 (kg)