It is known that the solution set of proposition P: inequality | x |+| x- 1 | > M is R, and proposition Q: function F (x) =-(7-3m) x is a decreasing function. If p or q is a true proposition and p and q are false propositions, the range of the number m is realistic.

Analysis: ∵ Proposition P: The solution set of inequality | x |+x- 1 | > m is R.

When x; m== >m & lt 1-2x

When 0

When x>= 1, x+x-1> m== >m & lt2x+ 1

t:m & lt； 1

Female: m>= 1

Proposition Q: The function f (x) =-(7-3m) x is a decreasing function.

t:7-3m & gt； 1== >m & lt2

f:0 & lt； 7-3m & lt； 1== >2 & ltm & lt7/3

∫p∨q = T = = & gt； Take the union of m < 1, m<2: m.

p∧q = F = = & gt； ┐p∨┐q=t==>； Take m>= 1, 2 <; Combination of m & lt7/3: m>= 1

When p or q is a true proposition, m

When p and q are false propositions, m>= 1

If P or Q is a true proposition and P and Q are false propositions, let their intersection be 1