∴∠DBE=∠DBC-∠EBC=60 -30 =30。

∫∠BCD = 90，

∴∠BDC=90 -∠DBC=90 -60 =30。

∴∠DBE=∠BDE.

∴BE=DE.

Let EC=x, then DE=BE=2EC=2x, DC=EC+DE=x+2x=3x,

BC=BE2？ EC2=(2x)2？ x2=3x，

From the topic, ∠ DAC = 45, ∠ DCA = 90, AB=20,

△ ACD is an isosceles right triangle,

∴AC=DC.

∴3x+20=3x，

Solution: x ≈ 15.77.

∴2x≈3 1.5.

A: Is the tower height about 3 1.5? Meter (short for meter))