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Primary school mathematics evaluation manual sixth grade volume 8 1 page answer
Handbook of Primary School Mathematics Evaluation, Grade 6, Volume 1, 865438+ Page 0 Answer 33, A, B and C run the 60-meter race. When Party A reaches the finish line, it is 10 meters ahead of Party B and 20 meters ahead of Party C. At the original speed, how many meters ahead of Party C will Party B reach the finish line?

Solution: A run 100m, B run 90m and C run 80m.

Set B to the finish line and C to run one meter.

therefore

90:80= 100:a

90a=8000

a=800/9

Leading C 100-800/9= 100/9 meters.

34. The bus and truck leave from A and B at the same time and meet in four hours. As we all know, the speed ratio of bus to truck is 7: 5. How many hours will it take for the truck to arrive at the post-meeting place?

Solution: Let the truck arrive at location A within one hour.

5/ 12:4=7/ 12:a

5/ 12a=7/ 12×4

A=28/5 hours

35. There are several red and white balls. The ratio of red ball to white ball is 5: 7. Later, six red balls were released. The ratio at this time is 1: 1. How many balls are there now?

Solution: There are 5a red balls and 7a white balls.

According to the meaning of the question

(5a+6):7a= 1: 1

7a=5a+6

2a=6

a=3

Now there is (5+7)×3+6=42.

36. There are 85 students in Class A and Class B, and Class B 1 1 is transferred to Class A, and the ratio of Class A to Class B is 9: 8. How many people are there in Class A?

Solution: There are A people in Class A, so there are 85-a people in Class B..

[a+(85-a)× 1/ 1 1]:(85-a)×( 1- 1/ 1 1)= 9:8

8a+8/ 1 1×(85-a)= 90/ 1 1×(85-a)

88a+680-8a=7650-90a

170a=6970

a=4 1

There are 4 1 person in class a.

37. Class A donated two-thirds of the sum of Class B and Class C, and Class B donated two-fifths of the sum of Class A and Class C. If Class A and Class B donated 144 yuan, how much did Class C donate?

Solution: class a donation a, class b donation144-a.

Class c donation (144-a)/(2/5)-a=360-7/2a.

According to the meaning of the question

a=( 144-a+360-7/2a)×2/3

3a=288-2a+720-7a

12a= 1008

A=84 yuan.

Then Class C donated 360-7/2×84=66 yuan.

38. The simplest fractional sums of two identical molecules are 1 and 18, and the ratio of the two denominators is 2: 3. What are the two scores?

Solution: Let denominators be 2a and 3a respectively.

therefore

1/(2a)+ 1/(3a)= 25/ 18

5/(6a)=25/ 18

a=3/5

Then these two scores are 5/6 and 5/9 respectively.

involve

Jiangsu Primary School Mathematics Evaluation Manual for Grade Six Page 55 Answers Jiangsu Education Edition Grade Six Evaluation Manual Standard Answers (New)

Unit 1 (Solving problems with column equation 1)

The first question (omitted)

2.( 1) Pears arrive (4x-20) kg. (2) Dad's weight is (3X+ 15) kg.

3. Solution: He walks X kilometers every hour. 3X﹢3= 18 3X= 18-3 X=5

4. Solution: The library covers an area of X square meters. 2X-20=400 2X=400+20 X=2 10

5. solution: there are x pear trees. X-500 = 1000 x2 X-500 = 2000 X = 2500

6. solution: Xiaohua is x years old. 3.2X-2.8X=6 0.4X=6 X= 15

Solving problems with column equations (2)

leave out

(1)3X=70+20 solution: 3x = 90x = 30 (2) 4x+15.5 = 23.54x = 23.5-15.5x = 2.

0.8 hectares =8000㎡ Solution: The height of the triangle is x meters. 200 X÷2 = 8000 200 X = 16000 X = 80

Solution: can stand x people. 16X = 20×24 16X = 480 X = 30

5. Solution: After expansion, X people can sit in each row on average. 36X = 36×30+432 36X = 15 12 X = 42

Column equation to solve the problem (3)

1.

2.( 1) Volleyball has (4X), volleyball has (4X+X), and basketball is less than volleyball (4X-X).

(2) There are (X+2.5X) pear trees and peach trees, and there are more pear trees than peach trees (2.5X-X).

3. Solution: There are X basketball and 3X football. 3X-X = 300 2X = 300 X = 150 3X = 150×3 = 450

4. Solution: The grain in warehouse B is XT, and the grain in warehouse A is 2.5xt.x+2.5x = 350 3.5x = 350x =100 2.5x =100× 2.5 = 250.

5. Solution: Warehouse B stores grain XT and Warehouse A stores grain 3XT. 3X-40 = X+40 3X-X = 40+40 2X = 80 3X = 40×3 = 120

6. Solution: warehouse A transports XT to warehouse B. 2× (180-x0 =120+x360-2x =120+x240 = 3xx = 80.

Column equation to solve the problem (4)

1.

2 ellipsis

3-5 Omission.

6. Solution: X black rabbits and 2X+4 white rabbits. X+2X+4 = 49 3X = 45 X = 15 2X+4 = 15×2+4 = 34

Review (1)

1-5 omitted

6. Set each exercise book to X yuan. 2X+ 1.8 = 4X-2.4 2X = 1.8+2.4 2X = 4.2 X = 2. 1 2X+ 1.8 = 2×2. 1+ 1.8 = 4.2+ 1.8 = 6

Review (2)

1-5 omitted.

6. Solution: X days after shipment. 2× 150 x = 350 x+900 500 x = 350 x+900 150 x = 900 x = 6 250 x = 250 x = 1500t 350 x+900 = 350 x 6+900 =

The first unit test

1.8XX+88x-X2X+ 10 2.5 x3x+2.5x×2 1 1+X+35s÷2÷5 5

Second, ③, ②, ③, ②, ③.

Third, ellipsis

4. 1-2 omitted, 3. Solution: The two cars will meet in X hours. 58X+25+62X = 985 120 X+25 = 985 120 X = 960 X = 8

4. Omit. 5. Solution: Huawei X Yuan. 2× (x-30 = x+85-30 2x-60 = x+55x =15x+85 = 1 15+85 = 200 (floret1/.

Unit 2: Understanding of Cuboid and Cube (1)

1 fill in the blanks. (1)6, 12, 8.(2) rectangle, 6㎝, 5㎝, 4㎝, 30 square centimeters, rectangle, 5㎝, 4㎝, 20 square centimeters. (3) Rectangular, 4㎝, 7㎝, 4㎝, square, 16㎝? , rectangle, 7㎝, 4㎝, 28㎝? .

2. Choice: ③, ①.

3 ellipsis.

Understanding of Cuboid and Cube (2)

1( 1) squared, 6, 12, 8, 4, 48 squared, 4, 16 (2) 15, 85, 5 1, squared and 6544.

2.60÷ 12=5㎝ 5×5=25㎝? (The side length is 5㎝ and the bottom area is 25㎝? )

3: 10×4=40㎝ 8×4=32㎝ 92-(32+40)=20㎝ 20÷4=5㎝ 10×8=80㎝? (height 5㎝, bottom area 80㎝? )

Surface area of cuboid and cube (1)

1. Fill in the blanks (1) 40,40,50,130 (2)15,6, 10, 162.

2: 3× 6× 2 = 36 square decimeter 4×6×2=48 square decimeter 3×4×2=24 square decimeter 36+24+48= 108 square decimeter (Xiao Gang thought)

(3×6)+(3×4)+(4×6)×2= 108 square decimeter (Xiao Juan thought)

3:(2×4)+(2×4)+(4×4)×2=64 square decimeter

4:30÷ 12=2.5㎝ 2.5×2.5=6.25㎝? 6.25×6=37.5㎝? (The bottom area is 6.25㎝? , surface area of 37.5㎝? )

Surface areas of cuboids and cubes (2)

1:②、①、②

2、94㎝? 、0.64㎡、384dm?

3. 1 m = 10 decimeter (10× 4+4× 410× 4) × 2 =192 square decimeter192-(4×

4. (8×10+6×/kloc-0+6× 8) × 2 = 376 square decimeter 376-6×8=328 square decimeter.

5:、96÷ 12㎝ 8×8×6=384㎝? 384-64=320㎝?

Surface areas of cuboids and cubes (3)

Omit 1

2、①、②

Omit 3-5

6、( 12× 1+ 1× 1+ 12×)×2=50㎝?

Volume of cuboid cube (1)

1, (1)-(3) slightly (4) cubic centimeters (5) cubic decimeter (6) liters.

2 choice, ③, ②, ②

3, 32 cubic centimeters, 64 cubic centimeters, 72 cubic centimeters, 1 12 cubic centimeters

Volumes of cuboids and cubes (2)

1-3 omitted

4,6 meters =60 decimeters 4×4= 16 square decimeters 60×4×4=960 cubic decimeters (cross-sectional area 16 square decimeters, volume 960 cubic decimeters)

5 ellipsis

Volumes of cuboids and cubes (3)

Omit 1

2、①、③

Omit 3-4

5、 10÷2=5㎝ 10×5×5=250㎝? (Volume 250㎝? )

Volumes of cuboids and cubes (4)

1、( 1)56、 1 12、64(2)、2、24、8 (3)、3、 1、 1、 14、3

2, fill in the form 384㎝? 、5 12㎝? 、 184dm? 、 160dm?

Omit 3-4

5、60÷3=20㎝ 20÷4=5㎝ 5+3=8㎝ 5×5×8=200㎝? (Volume 200㎝? )

Promotion rate between unit of volume (1)

1( 1)700、37、3240、6500、0.74、 1.25 (2)350、247、3500、2470

2-6 Omission

Promotion rate between unit of volume (2)

1, cubic centimeter, cubic decimeter, cubic centimeter, cubic meter, liter

2、700、5470、3600、3.8、3800、0.2、4900、4.9、2.5、750、750、4、2.4、2400

Omit 3-5

Promotion rate between unit of volume (3)

1, 3600,814,0.814,0.13,5 liters of 90 ml, 5090.

(2)>、=、、>、、=

3, 4, 5 ellipsis

Fractional Division Application (1)

1, total length ×4/7= repair length, number of girls ×4/5= number of boys, number of black rabbits × 1/8= number of white rabbits compared with the number of black rabbits, planned amount ×110 = actual savings compared with planned amount.

2, 3, 4 and 5 are omitted.

Application of Fractional Division (2)

Omit 1

2.9/10 ÷ 3/4× 9/10 = 27/25 (m2)

3,6/5 ÷ 2/5× 3/4 = 9/4 (km)

4.240×3/4÷6/7=2 10 (person)

check against the authoritative text

leave out

Unit 4 Testing

Illo

Fill in the blanks, 7/ 10, 5/8, 2/5, 10,10, 8/9÷4, 8/9× 1/4, >

Three choices, ①, ②, ①, ②.

Fourth, omit 1, 2,240× 2/3 ÷ 4 = 40 (page)

3, 4, 5 ellipsis

The meaning of ratio

1、5:7、5/7、7:5、7/5、32:5、32/5、4、9、4/9、 19、 16、 19、 16、5:4、5:4

2 ellipsis

3、9/5、 15/4、40

4. The travel time ratio of car A and car B is 6: 10, which is simplified to 3:5.

3÷5=3/5 ratio: 3/5.

The speed ratio between car A and car B is 80:48, which is simplified to 5:3.

5÷3=5/3 The ratio is 5/3.

Basic properties of ratio

1、32、30、28、 1: 1 1、5:6

2 ellipsis

3. Omission

4、2:7、3: 10、2:7

Application of ratio

1、4、5、9、4/9、5/9、2 1/65、9/26、43/ 130

2 ellipsis

3 omitted, 4( 1)400÷ 100=4(G)

(2) 1+ 100 = 10 1 3030÷ 1× 1 = 30(g)3030÷ 1008。

Unit 5 Testing

A blank, 2/3, 1/3, 15, 15,16,15,12,40,5: 4,/kloc-

2. Judgment, √, ×, √, √.

Three calculations

Omitted four 1, 2, 3, 4 and 5.

midterm examination

Fill in the blanks, 4/5, 1/6, 4/5, 15/8, 8/ 15, 7080, 2.25, 10 liter 50 ml, 3 minutes and 30 seconds, 72, 32.

Select ①, ②, ③, ③.

Three calculations

Omit four 1-6.

7. Surface area of cuboid: 10a? 4×2=8dm cubic surface area: 6a? 8×4×4= 128dm?

10a? -6a? =64 4a? =64 a? = 16a = 4 (the original cuboid wood volume is 128 cubic decimeter)

Abbreviation of fractional elementary arithmetic unit

The problem-solving strategy unit is omitted (these two units are relatively simple and don't write answers)

Unit 6 and Unit 7 Testing

A blank, 3/8, 16, 12, 9,11,289/70, 70/289, 3/7, 3/4, last year's income.

Two calculations are omitted.

Three choices, ③, ③, ②, ②,

4 PCs 1-5 omitted, 6 PCs, set, with x large bottles and 60-X small bottles. 4X+(60-X)×0.5 = 100 4X- 1/2X = 70 7/2X = 70 X = 20 60-X = 60-20 = 40

7. Solution: pear X box and apple 2/5X box. X+2/5x = 700 7/5x = 700x = 500 2/5x = 200 (200 boxes of apples and 500 boxes of pears).

8,26÷ 1/5 = 130(a) 130×4/5 = 104(a) 104×7/ 13 = 56(a)

The possibility is slim.

Significance of percentage

1, omitted

2、√、√、√、√、√

Conversion between Percent, Decimal and Fraction

Percentage unit abbreviation (simple unit abbreviation)

Unit 8 and Unit 9 Testing

Blank sheet, 4/3, 1. 13, 4, 25, 80, 12.5, 0. 125,18,96, unqualified, 4,/kloc.

Do a little calculation

3. Judgment, √, ×, √×.

Fourth, choose, ②, ②, ③, ①.

Five operational strategies

Sixth, ellipsis

final test

Simple calculation

Fill in the blanks, cuboid, 2,3500, 0.6,750, 36, ②, ①, 4.5, 30, 2:3, 3:5, 64, 37.5, 1/40, 62.5, 75, 95, 65438.

Draw "√"1,8,2,15,3,16/9,4,10; 1, 5, 1/2, 6, cannot be determined.

Wood unit of volume

Handbook of primary school mathematics evaluation, grade six, volume one, five or six pages, answer 1. Let x years later.

40+X=( 12+X)3

40+X=36+3X

4=2X

X=2

2. Set X days.

350X+900=250X*2

350X+900=500X

900= 150X

X=6

B warehouse 6*250= 1500 A warehouse 1500*2=3000.

I am the elder sister of Grade Two, and I hope I can help you.

I only have the 20 12 version of the math evaluation manual for the sixth grade of primary school.

P7, Mathematics Evaluation Manual for the Sixth Grade of Primary School Answer: Wen Ku. Baidu, please. /view/ 1 df 25 f 1 c 59 eef 8 c 75 FFB 397。

Absolutely right ~! ! ! ! !

The answer to the seventh question on page 55 of the mathematics evaluation manual for the sixth grade of primary school is endless. ╮ (╯ ▽ ╰) ╭ Just do this problem yourself.

I don't know the answer to the first volume of the sixth grade mathematics evaluation manual! Not if you don't write! ) Online search on Daqing Education!

I can't help you

The answers on pages 75, 76, 77 and 78 of the first volume of the sixth grade mathematics evaluation manual tell you a few.

1. 120、400

2. Five eighths, 0.625, 62.5%

7. 100、 144

8.96%

10.8 1

Think about the rest for yourself.

How to write the sixth question on the sixth page of the first volume of the mathematics evaluation manual for the sixth grade of primary school? Suppose that the goods have been delivered for X days, 350x+900x = 2x (250x) 350x+900x = 500x500x-350x = 900150x = 900x = 6a, there are 3000, and it has been 1500.

The answer on page 64 of the fifth grade mathematics evaluation manual is to write down the questions that you can't.