Current location - Training Enrollment Network - Mathematics courses - Pythagorean Theorem of Mathematics in Eighth Grade of Hebei Education Edition
Pythagorean Theorem of Mathematics in Eighth Grade of Hebei Education Edition
This problem is troublesome, so we have to draw a picture.

Rotate the triangle ABP 60 degrees around point B to CBQ, so that AB and CB coincide (P turns to Q).

Connecting PQ

Because BP=BQ, PBQ=60 degrees.

So the triangle BPQ is an equilateral triangle with PQ=PB=4 and the angle BQP=60 degrees.

Because PC=5 and CQ=AP=3.

So the square of CQ+the square of PQ = the square of PC

So CQP angle =90 degrees.

Because angle APB= angle CQP

So the angle APB=60+90= 150 degrees.