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Mathematical problems of work efficiency
I have a similar answer.

A single job takes 20 hours, while B is 4 hours more than A, and C is 2 hours more than half of A. If Party A and Party B work together first 10 hour, how many hours can Party C work alone?

Solution:

It takes 24 hours for B to work alone, and it takes 12 hours for C to work alone.

That is, 1/20 for A and 1/24 for B..

C do it every hour112.

Set it up now, and it can be completed in x hours.

A completed 1/20.

×

10= 1/2

B completed 1/24.

×

10=5/ 12

C complete112.

×

X

These three people added up to finish the whole work.

Column equation

1/2

+5/ 12

+

1/ 12

X

= 1

solve an equation

X= 1

So C worked alone for 1 hour.