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Math question: How old is Komatsu?
The ages are: Xiaomei A, Xiaolan B and Xiao Ju C; Komatsu is D, Xiaobai is E and Xiaoshan is F. The husbands of Xiaomei, Xiaolan and Xiao Ju are a', b' and c' respectively. Xiao Ju said, "Of the six people here, only my husband is eccentric. Xiao Shan said, "I am older than my wife 1 1 year. _ _ _ _ _ Knowing that Chrysanthemum is husband and wife, age ratio =(c+ 1 1)/c If Bolan is husband and wife, then (b+8)/b = (c+1)/c,1.

b+8

c

c+ 1 1) =( 16

24

22

33), at this time a+a'= 185-95=90 ... it is possible that __( 1) =(24.

32

33

44), a+a'=52 ... Maybe __(2) =(32

40

Forty-four

55), a+a'= 14 ... not (1)b

b'= 16

At 24 o'clock, b/b'=2/3=a/a', while a+a' = 90 3a = 2a', 2a+2a'= 180, 5a= 180, May =36 and Song A' = 54 May.

b'=24

At 32: 00, b/b'=3/4=a/a', a+a'=52 3a'=4a, 3a+3a'= 156, 7a= 156, and a is not an integer, so bridled, fir and Song Mei are husband and wife respectively. ...

Reference: mathland.idv/talk-over/memo? srcid = 23650 & amp; bname=ASP