b+8
c
c+ 1 1) =( 16
24
22
33), at this time a+a'= 185-95=90 ... it is possible that __( 1) =(24.
32
33
44), a+a'=52 ... Maybe __(2) =(32
40
Forty-four
55), a+a'= 14 ... not (1)b
b'= 16
At 24 o'clock, b/b'=2/3=a/a', while a+a' = 90 3a = 2a', 2a+2a'= 180, 5a= 180, May =36 and Song A' = 54 May.
b'=24
At 32: 00, b/b'=3/4=a/a', a+a'=52 3a'=4a, 3a+3a'= 156, 7a= 156, and a is not an integer, so bridled, fir and Song Mei are husband and wife respectively. ...
Reference: mathland.idv/talk-over/memo? srcid = 23650 & amp; bname=ASP