Because you didn't make it clear, this problem is divided into two situations.

1, the bottle is molded, that is, the sharp part is on it.

2, the bottle is V-shaped, that is, the sharp part is below.

The first case:

If the radius of the bottom surface is 2r and the radius at the half height of the container is r,

Let the total height of the container be 2h, then the height at the half height of the container is h,

And divides the container into an upper half and a lower half.

V-cone = 1/3* bottom area * height

The position of 10ml wine is the volume of the lower half.

Therefore, the volume of 10ml wine = the volume of the whole container-the volume of the upper part =1/3 * [(2r) 2 * 3.14] * 2h-1/3 * [R2 * 3./kloc-0.

=7/3*3. 14*(r^2*h)= 10

3. 14*(r^2*h)=30/7

How much wine to add is the volume of the upper part = (r 2 * 3. 14) * h = 30/7ml.

So, add 30/7ml of wine.

The second situation

If the radius of the upper bottom surface is 2r and the radius at the half height of the container is r,

Let the total height of the container be 2h, then the height at the half height of the container is h,

And divides the container into an upper half and a lower half.

V-cone = 1/3* bottom area * height

The position of 10ml wine is the volume of the lower half.

So 10ml wine volume = lower half volume =1/3 * (R2 * 3.14) * h =10.

1/3*(r^2*3. 14*h)= 10

How much wine to add is to find the volume of the lower part = the volume of the whole container-the volume of the upper part =1/3 * [(2r) 2 * 3.14] * 2h-1/3 * [R2 * 3.14] *.

=7/3*3. 14*(r^2*h)

=7*[ 1/3*(r^2*3. 14*h)]=7* 10=70ml

So, add 70 ml of wine.