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Mathematics: a permutation and combination problem
The first case:

Male preference: p (4 4,4) = 4× 3× 2×1= 24 species.

Reordered females: P (4 4,4) = 4× 3× 2×1= 24 species.

Addition principle: 24+24=48 species.

The second case:

The first female: P (4 4,4) = 4× 3× 2×1= 24 species.

Ranked males: p (4 4,4) = 4× 3× 2×1= 24 species.

Addition principle: 24+24=48 species.

Total number ***:48+48=96 species.