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Find a math problem with a high probability of three years.
Once: all three colors are the same 2/(6 * 5 * 4/3 * 2 *1) = 0.1.

What's left is that two colors are the same and one is different, 1-0. 1=0.9.

Three times: the probability of not winning the first prize once =0.9*0.9*0.9=0.729.

Probability of winning the first prize at least once = 1-0.729 = 0.25438+0.