The photon energy released when the atom transitions from energy level n=3 to n=2 is 3.40-1.51=1.89 ev. When the photon energy equals the work function, the photoelectric effect occurs, so the work function W0 = 1.89 EV.

The photon energy released by the transition from energy level n=4 to n= 1 is13.6-0.85 ev =12.75 ev. According to the photoelectric effect equation, the maximum initial kinetic energy ekm = HV-w0 =12.75-1.89 =

So the answer is: 1.89, 10.86.