VB-ADFE= 13SADFE? AB= 1。
(2) If the midpoint H of AB is taken, HG∨AD, so ∠HGE is the angle formed by straight line EG and AD.
AG=5,EG=6,HG=2,EH=2。
Therefore, in Rt△EHG, tan ∠ egh = ehhg = 22.
That is, the angle between the straight line EF and AG is arctan22. ..