∵ABCD is a rectangle.

∴ Angle abc = 90

In RT△ABC

AB？ +BC？ =AC？

AB = 6，BC=8

∴AC= 10

∵PE⊥OB

Angle BEP = 90

And ∵AC and BD are the bisectors of ABCD.

∴ Angle EBF= Angle FCP

∴△EPB∽△ACB

PE:AB=PB:AC

PE = 3X times /5

Similarly: PF=(24-3X)/5

That is, PE+PF=(24-3X+3X)/5

=24/5 fractional answer

=4.8 Decimal answer

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