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Junior high school mathematics problem-solving area
1, according to Pythagorean theorem, the right-angle side length √ [(4 √ 2) 2/2] = 4.

The area is 4*4* 1/2=8.

2. The length of the midline of the hypotenuse is equal to 65438+ 0/2 of the hypotenuse, and the hypotenuse length c=2.

The sum of right angles is equal to a+b=2+√6-2=√6.

Sum of squares of right angles A 2+B 2 = C 2 = 4

s= 1/2*ab= 1/4*[(a+b)^2-(a^2+b^2)]= 1/4*2= 1/2