(x-2)(x+ 1)>0

X<- 1, x>2, x is an integer.

B

(2x+5)(x+k)& lt； 0

Zero is -5/2 and-k.

If -k < -5/2, k & gt5/2

Then-k < x <; -5/2, where x=-2 is not within this range.

Does not satisfy A = {-2},

so-k & gt； -5/2，k & lt5/2

Then -5/2

Including -2 -k >-2

k & lt2

Because the intersection has only one integer -2.

A is X.

He does not include-1, 0, 1, 2.

So it's ok if b includes these numbers.

So as long as x

So-k < =3，k & gt=-3

To sum it up

-3≤k & lt； 2