(a-d)+a+(a+d)= 120
∴3a= 120
∴a=40 and 4(a-d)+5=a+d:
4(40-d)+5=40+d
∴ 160-d+5=40+d
∴d=25
Solving binary linear equations is generally to add, subtract and eliminate the elimination period.
However, this question is relatively simple. The first equation directly eliminates D to solve A, and then substitutes it into the second equation to solve D..