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Evaluation of Mathematics Simplification in Grade Seven
(3X+2Y)+(4X+3Y) where x = 5 and y+3.

Solution: The original formula =3X+2Y+4X+3Y=7X+5Y.

When x = 5 and y = 3.

Original formula =5*7+(-3)*5+20.

2.(5a 2-3b 2)+(a 2+b 2)-(5a 2+3b 2), where a =- 1 and b = 1.

=5a^2-3b^2+a^2+b^2-5a^2-3b^2

=a^2-5b^2

=(- 1)^2-5* 1^2

= 1-5

=-4

3.2 (A2B+AB 2)-2 (A2B-1)-2AB 2-2 where a =-2 and b = 2.

=2a^2b+2ab^2-2a^2b+2-2ab^2-2

=0

1. It is known that A and B are two real roots of the equation x 2+2x-5 = 0.

Find the value of (a 2+2ab+2a) (b 2+2ab+2b).

Derived from the fact that A and B are two real numbers of the equation x 2+2x-5 = 0:

AB=-5,A+B=-2

A^2+2AB+2A)(B^2+2AB+2B)

=AB(A+2B+2)(B+2A+2)

=-5(-2+B+2)(-2+A+2)

=-5AB

=25

2, 1/2(x+y+z) squared+1/2 (x-y-z) (x-y+z)-z (x+y), where x-y=6 and xy=2 1. Be specific.

Simplify:

1/2(x+y+z) squared+1/2 (x-y-z) (x-y+z)-z (x+y) =1

1/2[(x+y) square +2z(x+y)+z square ]+ 1/2[(x-y) square -z square ]-z(x+y)=]

1/2(x+y) square+1/2(x-y) square =x square +y square.

From x-y=6, xy=2 1, x+y = (x-y)+2xy = 78.

3. Find the value of 2ab-2a 2-4b 2-7 from a 2-ab+2b 2 = 3.

2ab-2a^2-4b^2-7

=2(ab-a^2-2b^2)-7

=-2(a^2-ab+2b^2)-7

=(-2)*3-7

=-6-7=- 13

4. If A = 2x 2+3xy-2x-3, B =-x 2+xy+2, and the value of 3A+6B has nothing to do with X, find the value of y..

Solution:

3a+6b=6x^2+9xy-6x-9-6x^2+6xy+ 12

= 15xy-6x+3

=x( 15y-6)+3

5.9x+6x 2-3 (x-2/3x 2), where x=-2.

9x+6x -3(x-2/3x)

=9x+6x-3x+2x

=8x+6x

=8×(-2)+6×(-2)

=32- 12

=20

6.1/4 (-4x2+2x-8)-(1/2x-1), where x= 1/2.

1/4(-4x+2x-8)-( 1/2x- 1)

=-x+ 1/2x-2- 1/2x+ 1

=-x- 1

=-( 1/2)- 1

=- 1/4- 1

=-5/4

7.3x' y-[2x' y-(2xyz-x' z)-4x' z]-XYZ, where x =-2, y =-3, z = 1,

:3x ' y-[2x ' y-(2xyz-x ' z)-4x ' z]-XYZ

=3x'y-2x'y+2xyz-x'z+4x'z-xyz

=x'y-xyz+3x'z

=4*(-3)-2*3* 1+3*4* 1

=- 12-6+ 12

=-6

8.(5a 2-3b 2)+(a 2+b 2)-(5a 2+3b 2), where a =- 1 and b = 1.

=5a^2-3b^2+a^2+b^2-5a^2-3b^2

=a^2-5b^2

=(- 1)^2-5* 1^2

= 1-5

=-4

9,2 (A2B+AB 2)-2 (A2B-1)-2AB 2-2, where a =-2 and b = 2.

=2a^2b+2ab^2-2a^2b+2-2ab^2-2

=0

10 squared, (x-21y-1) (x-21y+1)-(x-21y-1).

Where x = 1.7 and y = 3.9 (simplify first and then evaluate).

[(X-2 is 1Y)- 1][(X+2 is 1Y)+ 1]-(X-2 is1y-0/) square.

= (x+ 1Y) square-1-(x- 1Y) square +2 (x- 1Y)- 1.

= (x+ 1Y) square -(x- 1Y) square +2 (x- 1y) -(X-2

=2XY+2X-Y-2

=3.9*2.4+ 1.4

= 10.76

1. It is known that A and B are two real roots of the equation x 2+2x-5 = 0.

Find the value of (a 2+2ab+2a) (b 2+2ab+2b).

Derived from the fact that A and B are two real numbers of the equation x 2+2x-5 = 0:

AB=-5,A+B=-2

A^2+2AB+2A)(B^2+2AB+2B)

=AB(A+2B+2)(B+2A+2)

=-5(-2+B+2)(-2+A+2)

=-5AB

=25

2, 1/2(x+y+z) squared+1/2 (x-y-z) (x-y+z)-z (x+y), where x-y=6 and xy=2 1. Be specific.

Simplify:

1/2(x+y+z) squared+1/2 (x-y-z) (x-y+z)-z (x+y) =1

1/2[(x+y) square +2z(x+y)+z square ]+ 1/2[(x-y) square -z square ]-z(x+y)=]

1/2(x+y) square+1/2(x-y) square =x square +y square.

From x-y=6, xy=2 1, x+y = (x-y)+2xy = 78.

3. Find the value of 2ab-2a 2-4b 2-7 from a 2-ab+2b 2 = 3.

2ab-2a^2-4b^2-7

=2(ab-a^2-2b^2)-7

=-2(a^2-ab+2b^2)-7

=(-2)*3-7

=-6-7=- 13

4. If A = 2x 2+3xy-2x-3, B =-x 2+xy+2, and the value of 3A+6B has nothing to do with X, find the value of y..

Solution:

3a+6b=6x^2+9xy-6x-9-6x^2+6xy+ 12

= 15xy-6x+3

=x( 15y-6)+3

5.9x+6x 2-3 (x-2/3x 2), where x=-2.

9x+6x? -3(x-2/3x? )

=9x+6x? -3x+2x?

=8x? +6 times

=8×(-2)? +6×(-2)

=32- 12

=20

6.1/4 (-4x2+2x-8)-(1/2x-1), where x= 1/2.

1/4(-4x? +2x-8)-( 1/2x- 1)

=-x? + 1/2x-2- 1/2x+ 1

=-x? - 1

=-( 1/2)? - 1

=- 1/4- 1

=-5/4

7.3x' y-[2x' y-(2xyz-x' z)-4x' z]-XYZ, where x =-2, y =-3, z = 1,

:3x ' y-[2x ' y-(2xyz-x ' z)-4x ' z]-XYZ

=3x'y-2x'y+2xyz-x'z+4x'z-xyz

=x'y-xyz+3x'z

=4*(-3)-2*3* 1+3*4* 1

=- 12-6+ 12

=-6

8.(5a 2-3b 2)+(a 2+b 2)-(5a 2+3b 2), where a =- 1 and b = 1.

=5a^2-3b^2+a^2+b^2-5a^2-3b^2

=a^2-5b^2

=(- 1)^2-5* 1^2

= 1-5

=-4

9,2 (A2B+AB 2)-2 (A2B-1)-2AB 2-2, where a =-2 and b = 2.

=2a^2b+2ab^2-2a^2b+2-2ab^2-2

=0

10 squared, (x-21y-1) (x-21y+1)-(x-21y-1).

Where x = 1.7 and y = 3.9 (simplify first and then evaluate).

[(X-2 is 1Y)- 1][(X+2 is 1Y)+ 1]-(X-2 is1y-0/) square.

= (x+ 1Y) square-1-(x- 1Y) square +2 (x- 1Y)- 1.

= (x+ 1Y) square -(x- 1Y) square +2 (x- 1y) -(X-2

=2XY+2X-Y-2

=3.9*2.4+ 1.4

= 10.76

11.(3x+2y)+(4x+3y) where X=5, Y+3.

Solution: The original formula =3X+2Y+4X+3Y=7X+5Y.

When x = 5 and y = 3.

Original formula =5*7+(-3)*5+20.

12. (5a2-3b2)+(a2+b2)-(5a2+3b2), where a =- 1 and b = 1.

=5a^2-3b^2+a^2+b^2-5a^2-3b^2

=a^2-5b^2

=(- 1)^2-5* 1^2

= 1-5

=-4

13.2 (a2b+ab2)-2 (a2b-1)-2ab2-2, where a =-2 and b = 2.

=2a^2b+2ab^2-2a^2b+2-2ab^2-2

=0

14.2 a-(3a-2 b+2)+(3a-4 b- 1)=),a=b= 1

=2a-3a+2b-2+3a-4b- 1

=(2-3+3)a+(2-4)b+(-2- 1)

=2a-2b-3=-3

15.5-( 1-x)- 1-(x- 1),x= 1 1

=5- 1+x- 1-x+ 1

=4

③2x-(x+3y)-(-x-y)-(x-y)=()

=2x-x+3y+x+y-x+y

=x+5y

a=2,b=4

Found 2(a-b-54)+3(a+b)

=5a+b- 108

=5*2+4- 108

=-94

a=b= 1

Found a+b-2(a-b+ 1)

=-a+3b-2

=- 1+3-2

=0

26.-(2 x2-y2)-[2 y2-(x2+2xy)]= _ _ _ _ _ _。

27. If -3a3b2 and 5ax- 1by+2 are similar terms, then x = _ _ _ _ _, and y = _ _ _ _ _.

28.(-y+6+3 y4-y3)-(2 y2-3 y3+y4-7)= _ _ _ _ _ _。

29. The result of simplifying the algebraic expression 4x2-[7x2-5x-3( 1-2x+x2)] is _ _ _ _.

30.2 a-B2+c-D3 = 2a+()-D3 = 2a-D3-()= c-()。

3 1.3a-(2a-3b)+3(a-2b)-b = _ _ _ _ _ _。

32. The simplified algebraic expression x-[y-2x-(x+y)] is equal to _ _ _ _.

33.[5a 2+()a-7]+[()a2-4a+()]= a2+2a+ 1。

34.3x-[y-(2x+y)]=______。

35.Simplify | 1-x+y |-x-y | (where x < 0, y > 0) equals _ _ _ _.

36. It is known that x≤y, x+y-| x+y-| x-y | = _ _ _ _ _

37. Given x < 0 and y < 0, simplify | x+y |-| 5-x-y | = _ _ _.

38.4a2n-an-(3an-2a2n)=______。

39. If you add -3x2y+2x2-3xy-4 to a polynomial, you get.

2x2y+3xy2-x2+2xy,

Then this polynomial is _ _ _ _.

40.-5xm-xm-(-7xm)+(-3xm)=______。

4 1. When a=- 1 and b=-2,

[a-(b-c)]-[-b-(-c-a)]=______。

43. When a=- 1, b= 1 and c=- 1,

-[b-2(-5a)]-(-3b+5c)=______。

44.-2(3x+z)-(-6x)+(-5y+3z)=______。

45.-5an-an+ 1-(-7an+ 1)+(-3an)= _ _ _ _ _ _。

46.3 a-(2a-4 b-6c)+3(-2c+2b)= _ _ _ _ _ _。

48.9 a2+[7 a2-2a-(-a2+3a)]= _ _ _ _ _ _。

50. When 2y-x=5, 5 (x-2y) 2-3 (-x+2y)-100 = _ _ _.