2 F(x) is odd function, and it is increasing function when it is greater than 0. From F(x)=-F(-X) (you can also draw a picture to understand that odd function is symmetrical about the origin), it is easy to know that when F(x) is less than 0, it is also increasing function, and F(x) is increasing. Obviously, f (x) = 1/.

3 f (-x)-g (-x) =-f (x)-g (x) = (-x) * (-x)+2 = x * x+2 From the properties of odd function and even functions on both sides of the equation, it is easy to solve the two equations as long as they are simultaneous. ...

4 inequality can be reduced to f (1-m)

5 f(-x)=x*x+|x-2|- 1=f(x), so it is an even function, so the minimum value of f(x) is the minimum value when x is greater than 0; when 0 =3/4, when x is greater than or equal to 2, the minimum value is 3; when x is 0, f (0).

Because f(x) is odd function, the domain of x should be symmetrical about the origin. Because ax= 1, when a is not 0, x= 1/a, so we can only take x=0. That is, a is infinite, and when a=0, the function is undefined on R.

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