So c>8 c=(a+200)0.4 c=2/5a+80 a must be a multiple of 5.
When a=5 b= 13 c=82
a= 10 b=6 c=84
A= 15 b=- 1 c=86 is invalid.
So the answer is (1)a=5 b= 13 c=82.
(2)a= 10 b=6 c=84
When there are five big men, 13 big women and 82 children, each person moves 20, 39, 4 1 brick.
When 18 men, 6 women and 84 children each moved 4018,42 bricks.