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20 13 Mathematics Shunyi No.2 Module
(1) As can be seen from the figure, when the depth of the poured liquid is 0, the pressure of the block at the bottom of the container is F=G=20N.

When the depth of the poured liquid h=4cm=0.04m, the pressure of the block at the bottom of the container f ′ =15n, while f ′ = g-f floats.

∴F float =G-F'=20N- 15N=5N,

∫F float =ρ liquid v row g=ρ liquid Shg,

∴ density of liquid:

ρ liquid =F floating SHG = 5n10x10x10? 4 m2×0.04m× 10N/kg = 1.25× 103kg/m3;

(2)∫G = mg =ρVg,

Density of block:

ρobject = GVG = 20n 10× 10× 10× 10? 6 m3× 10N/kg = 2× 103kg/m3,

∵ ρ substance >ρliquid,

When the depth of the poured liquid is h ′ =12 cm, the wood block will be immersed in the liquid and sink to the bottom of the container.

Pressure at the bottom of the container:

F pressure =G-F floating' =20N-ρ liquid VG = 20n-1.25x103kg/m3×10x10x.

Therefore, the answer is:1.25x103kg/m3; 7.5N。