Let the straight line passing through d ﹙1,3 ﹚ and 4 ﹙1﹚ be y = kx+b ﹙ k ≠ 0.
k+b=﹣3,﹣4k+b=﹣ 1
The solution is k =-0.4 and b =-2.6.
The coordinates of the intersection q of the straight line E'd and the straight line l can be obtained by solving the equations Y =-0.4x-2.6 and y = x.
x=﹣ 13/7,y=﹣ 13/7
∴Q﹙﹣ 13/7,﹣ 13/7﹚