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"Triangle" Geometry Problem in Junior Two Mathematics
The correct angle is class = Cao.

Proof: Because Angel MBA= Angel ABN

So AB bisects the MBC angle

Angle MBA= 1/2 Angle MBC

Because angle MCA= angle ACN

So the AC bisection angle MCB

Angle ACN= 1/2 Angle MCB

So point A is the center of the triangle MBC.

So AMB angle = 1/2 angle BMC.

Because angle BAN= angle AMB+ angle MBA

So the angle BAN= 1/2 (angle BMC+ angle MBC).

Because angle MBC+ angle BMC+ angle MCB= 180 degrees.

So angle MCB= 180- angle MBC- angle BMC.

So the angle BAN=90 degrees angle ACN.

Because angle CAO+ angle AOC+ angle ACN= 180 degrees.

Angle AOC=90 degrees

So the angle CAO=90 degrees angle ACN

So Jiaoban = Jiaocao

Therefore, it is correct that Jiao Ban = Jiao Cao.