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Mathematics estimation problem of sixth grade in primary school
Formula method:

There are four books for each person in grade five and three books for each person in grade six, so 7 16 books should be distributed.

Then 7 16 books = 3 books in grade 5 and grade 6 +65438+ 0 books in grade 5.

In the same way, 705 books = 3 books per person in grade 5 and 6+ 1 book per person in grade 6.

7 16-705= number of fifth graders-number of sixth graders = 1 1.

So 7 16 books = 4 books per person in grade 5+3 books per person in grade 6, which can be regarded as

7 16 books = 7 books per person in the sixth grade+165438+ 0 books per person; Seven books for each sixth grade = 716-11× 4 = 672;

There are 672÷7=96 students in Grade 6.

Grade five students are 96+ 1 1= 107.

The algebraic expression [716-(716-705) × 4] ÷ 7 = 96 people.

96+ 1 1= 107 people

A: There are 96 students in Grade 5 107 and Grade 6.

Equation method:

Solutions; Suppose there are x people in the fifth grade and y people in the sixth grade.

4x+3y = 7 16①; 3x+4y = 705②;

①×3-②×4,x= 107,y=96。

A: There are 96 students in Grade 5 107 and Grade 6.