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Several common problems in junior high school mathematics
Analysis: (1) Observing the table, it is not difficult to find that there are 1 table with 2 people on the basis of 4 people 1 table. When there are n tables, there are 4+2 (n-1) = 2n+2;

(2) First, calculate that four tables can sit 10, and * * has an arrangement of 60÷4= 15, then * * can sit 150;

(3) If four tables are square and can seat eight people, then 15×8= 120 people.

Solution: (1)4+2=6, 6+2=8, 4+2 (n-1) = 2n+2;

(2)(2×4+2)×(60÷4)= 150;

(3)2×4×(60÷4)= 120.