Students, there is usually only one answer to the math problem we do, but under special circumstances, there is more than one answer, that is, when you think about the problem from different angles, the answer is different. The chartering problem is one of them.

There are 50 students going boating, each big boat can take 6 people, and the rent is 10 yuan; Each boat can take four people and rent 8 yuan. If you are the leader, how are you going to charter a boat? What is the most economical way to rent a house?

Through calculation, I found that the number of big ships is 1 yuan, and the number of small boats is 2 yuan, so it is better to have more big ships and fewer small boats, so the seats are just full and the cost is the least.

How to determine the number of big ships and small boats? I want to list all the chartering methods and find the most economical one.

Through the list, the answer is clear at a glance. Rent seven big boats and two small boats. It happens that everyone has a seat and the rent is the least. And it is the same as my conclusion through calculation. How about I be the team leader?

This problem was finally solved by me. It seems that the list method is really a good helper to do math problems!