Question 1: First, ABD/PDC is an isosceles right triangle, then parallel lines of CD intersect, BD intersects at H point, and BC intersects at G point. It is easy to know that AHB is an isosceles right triangle and DABG is a square. Secondly, PA=3 times the root number 2, AH= 3 times the root number 2, which is half of AP, and because AHP is a right triangle, the angle HAP is 60 degrees.

Question 2: According to the first question, DABG is a square, so H is the key point, so it is the center line of PAC, so it is parallel to PC, and it is in the plane EBD, so it is proved.

I wrote this simple question, but it is correct. You should pay attention to the logical relationship. The college entrance examination will not test this logic question in the second question, because it pays more attention to written explanation.