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Formula for calculating the surface area and volume of tapered slope of bridge?
1. Calculation formula of surface area and volume of geometric body

Cylinder:

Surface area: 2πRr+2πRh Volume: πRRh (R is the radius of the upper and lower bottom circles of the cylinder, and H is the height of the cylinder)

Cone:

Surface area: π RR+π R [square root of (hh+RR)] Volume: πRRh/3 (r is the radius of the cone's low circle, and H is its height,

2 plane graphics

Name symbol perimeter c and area s

The length of side a of a square is c = 4as = a2.

The length of a side and b side of a rectangle C = 2 (A+B) S = AB.

Triangle a, b, C- has three sides, H-A, height S- half of the circumference, a, b, C- inner angle, among which

S =(a+b+c)/2s = ah/2 = ab/2 sinC =[S(S-a)(S-b)(S-c)] 1/2 = a2 sinbsinc/(2 Sina)

Quadrilateral d, D- diagonal length α-diagonal angle S = d, D-/2 sin α

Parallelogram a, b- side length h- side height α-included angle s = ah = absin α.

Diamond A- side length α-included angle D- long diagonal length D- short diagonal length S = DD/2 = A2Sinα

Trapezoids a and b- upper and lower base length h- height m- midline length s = (a+b) h/2 = MH.

Circle r- radius d- diameter c = π d = 2π rs = π R2 = π d2/4.

Sector r- sector radius a- degree of central angle c = 2r+2π r× (a/360) s = π R2× (a/360)

Bow L- arc length S = R2/2 (π α/ 180-sin α)

B chord length = R2arccos [(r-h)/r]-(r-h) (2RH-H2)1/2.

H vector height = π α R2/360-b/2 [R2-(b/2) 2]1/2.

R- radius = r (l-b)/2+BH/2.

Degree of α-central angle ≈2bh/3

Ring r- excircle radius s = π (R2-R2)

R- radius of inner circle = π (D2-D2)/4

D- cylinder diameter

Diameter of inner circle

Ellipse d- major axis s = π DD/4

D- minor axis

3 supplementary edition

plane graph

Name symbol

Perimeter c and area s

The length of side a of a square is c = 4a.

S=a^2

rectangle

The length of side a and side b is c = 2 (a+b).

S=ab

triangle

A, b, C- trilateral length

Height of h-a edge

Half the circumference

A, b, c- internal angle

Where s = (a+b+c)/2s = ah/2.

=ab/2 sinC

=[s(s-a)(s-b)(s-c)] 1/2

=a^2sinBsinC/(2sinA)

quadrilateral

D, d- diagonal length

α diagonal angle s = DD/2 sin α

parallelogram

Length of a and b sides

Height of h-a side

α-included angle between two sides s = ah

=absinα

diamond

Length of side a

α-included angle

D- long diagonal length

D- short diagonal length s = DD/2

=a^2sinα

trapeziform

A and b- the length of the upper and lower bottoms

up level

M- centerline length s = (a+b) h/2

=mh

circle

R radius

D- diameter c = π d = 2π r

S=πr^2

=πd^2/4

department

R- sector radius

Degree of central angle

C=2r+2πr×(a/360)

S=πr^2×(a/360)

arch form

L- arc length

B chord length

H vector height

R radius

The degree of α-central angle s = r 2/2 (π α/ 180-sin α)

=r^2arccos[(r-h)/r——(r-h)(2rh-h^2) 1/2

=παr^2/360-b/2[r^2-(b/2)^2] 1/2

=r(l-b)/2 + bh/2

≈2bh/3

ring

R- excircle radius

R- radius of inner circle

D- cylinder diameter

D- diameter of inner circle s = π (r 2-r 2)

=π(D^2-d^2)/4

oblong

D long axis

D- minor axis s = π DD/4

Cubic figure

Name symbol

Area s and volume v

The side length of cube a is s = 6a 2.

V=a^3

Cubic

Achang

B width

C- height s = 2 (AB+AC+BC)

V=abc

prism

S- bottom area

H- height v = sh

pyramid

S- bottom area

H- height v = sh/3

frustum of a pyramid

S 1 and S2- upper and lower bottom areas

H- height v = h [s1+S2+(s1S2)1/2]/3.

Prismatic

S 1- upper bottom area

S2- bottom area

S0- Cross-sectional area

H- height v = h (s 1+S2+4s0)/6.

column

R- bottom radius

up level

Bottom circumference

S- bottom area

S-side-lateral area

S table-surface area c = 2π r

S base = π r 2

S side = ch

S table = ch+2s bottom

V = s bottom h

=πr^2h

Hollow cylinder

R- excircle radius

R- radius of inner circle

H- height v = π h (r 2-r 2)

Straight cone

R- bottom radius

H- height v = π r 2h/3

Circular truncated cone

R- upper bottom radius

R- bottom radius

H- height v = π h (r 2+RR+r 2)/3

ball

R radius

D- diameter v = 4/3 π r 3 = π d 3/6

Bulb deficiency

H-ball missing height

R sphere radius

A- Radius of ball bottom v = π h (3a 2+h 2)/6.

=πh^2(3r-h)/3

a2=h(2r-h)

table

R 1 and R2- the radius of the top and bottom of the table.

H- height v = π h [3 (r 1 2+R2 2)+h 2]/6.

receptacle

R-ring radius

D-ring diameter

R-ring section radius

D-ring section diameter v = 2π 2rr 2

=π2Dd^2/4

staving

D- drum belly diameter

D- barrel bottom diameter

H- barrel height v = π h (2d 2+d 2)/ 12.

(The bus is circular, and the center of the circle is the center of the bucket)

V=πh(2D^2+Dd+3d^2/4)/ 15

(The bus is a parabola) References:

/blog/static/6708396220092263121/

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Answer time: March 29th, 2009 15: 44 | Let me comment.

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Cuboid:

Surface area: 2(ab+ah+bh)

Volume: abh(a is the length of the cuboid, b is the width of the cuboid, and h is the height of the cuboid)

Cube:

Surface area: 6a^2

Volume: A 3 (A is the side length of the cube)

Cylinder:

Surface area: 2π r 2+2π rh

Volume: π r 2h (R is the radius of the upper and lower bottom circles of the cylinder, and H is the height of the cylinder)

Cone:

Surface area: π r 2+π r radical (H 2+R 2)

Volume: π r 2h/3 (R is the radius of the cone's low circle and H is its height)

Surface area of regular prism and regular pyramid

Let the height of the prism be h and the perimeter of the bottom polygon be c, then the lateral area formula of the right-angled prism is: s right-angled prism lateral area = CH.

That is to say, the side area of a right-angled prism is equal to the product of its bottom perimeter and height.

Let the side length of the bottom surface of a regular pyramid be a, the perimeter of the bottom surface be c, and the inclined height be h', then the lateral area formula of the regular pyramid is:

Right side of the pyramid = nah' = ch'

That is to say, the side area of a regular pyramid is equal to half of the product of the perimeter of its bottom surface and the oblique height.

The surface area or total area of prism and pyramid is equal to the sum of lateral area and base area.

Prism surface area

Let the side length of the lower bottom surface of the prism be a, the perimeter of the prism be c, the side length of the upper bottom surface be a', the perimeter be c', and the inclined height be h', then the formula of the side area of the regular prism can be obtained.

S prism edge = n(a+a')h'=(c+c')h'

The surface area or total area of a prism is equal to the sum of the side area and the bottom area.

Go and see here.

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