20+80×3 7×(34+56) 105×2×5
800-57×9 (65+ 16)÷9 230×( 140- 132)
24×5+24×7 (2534-958)÷8 792×7÷9
(502 1-39 18)×6 1208-237×5 4280÷( 19- 1 1)
190+360÷24×8 ( 140+60)×(26-8) 78×7+828÷ 18
(359-42)×53+64 280 + 650 ÷ 13 1000 -(280 + 650 ÷ 13)
707 - 35 × 20 ( 120 - 103)× 50 50+ 160÷40 (58+370)÷(64-45)
120- 144÷ 18+35 760 ÷ 10 ÷ 38 (95 - 19 × 5 )÷74
45 × 20 × 3 (270 + 180)÷(30 - 15) 347+45×2-4 160÷52 95÷(64-45)
178- 145÷5×6+42 420+580-64×2 1÷28
8 12-700÷(9+3 1× 1 1) ( 136+64)×(65-345÷23)
85+ 14×( 14+208÷26)
(284+ 16)×(5 12-8208÷ 18)
. 120-36×4÷ 18+35
(58+37)÷(64-9×5)
. (6.8-6.8×0.55)÷8.5
0. 12× 4.8÷0. 12×4.8
(3.2× 1.5+2.5)÷ 1.6
10. 15- 10.75×0.4-5.7
In the third grade, I will go to the market 60 times next semester. I don't want answers. When I meet a question that I can't answer, I will go online to find the answer and copy it down. I don't want to think at all, which will help students develop. I can't ask the answer online.
The habit of not thinking, correct it, think more about doing problems, and be afraid of not thinking.
It depends on the purpose of your training and your child's learning ability. I think it's good to learn the first book of new concepts or Cambridge English, but children are willing to learn and recite it.
Practice oral arithmetic by stars every day, and practice the third grade answer in class next semester: 1 Grade Mathematics (Volume II), unit measurement, good final exam routines and good variants.
The main contents of this book include: numbers in life, observation and measurement, addition and subtraction (1), interesting graphics, addition and subtraction (2), shopping, addition and subtraction (3), statistics and so on.
English newspapers and periodicals answer 2 1 in the third semester. Concert, other courses. Can you have to
Three. Studying for thanking too much, I went to the movies on Wednesday.
The problem of aliasing calculation in the third grade of primary school in the next semester is 0.35× 1.6+0.35×3.4.
0.25×8.6×4
6.72-3.28- 1.72
0.45+6.37+4.55
5.4+6.9×3-(25-2.5)2×4 1846-620-380
4.8×46+4.8×54
0.8+0.8×2.5
1.25×3.6×8×2.5- 12.5×2.4
28× 12.5- 12.5×20
23.65-(3.07+3.65)
Find 600 off-line calculation questions for the third grade of primary school next semester, 2800 ÷100+789 (947-599)+76× 64.
1.36×(9 13-276÷23) 2.(93+25×2 1)×9
3.507÷ 13×63+498 4.723-(52 1+504)÷25
5.384÷ 12+23×37 1 6.(39-2 1)×(396÷6)
( 1) 156×[( 17.7-7.2)÷3] (2)[37.85-(7.85+6.4)] ×30
(3)28×(5+969.9÷3 18) (4)8 1÷[(72-54)×9]
57× 12-560÷35 848-640÷ 16× 12
960÷( 1500-32×45) [ 192-(54+38)]×67
138×25×4 ( 13× 125)×(3×8) ( 12+24+80)×50 704×25 25×32× 125 32×(25+ 125)
178× 10 1- 178 84×36+64×84 75×99+2×75 83× 102-83×2 98× 199
123× 18- 123×3+85× 123 50×(34×4)×3 25×(24+ 16) 178×99+ 178
79×42+79+79×57 7300÷25÷4 8 100÷4÷75 75×27+ 19×2 5 3 1×870+ 13×3 10
4×(25×65+25×28) 138×25×4 ( 13× 125)×(3×8) ( 12+24+80)×50
25×32× 125 32×(25+ 125) 102×76 58×98
178× 10 1- 178 84×36+64×84 75×99+2×75 83× 102-83×2
98× 199 123× 18- 123×3+85× 123 50×(34×4)×3 25×(24+ 16)
178×99+ 178 79×42+79+79×57 7300÷25÷4 8 100÷4÷75 .280+840÷24×5 2.85×(95- 1440÷24)
3.58870÷( 105+20×2) 4.80400-(4300+870÷ 15)
5. 1437×27+27×563 6.8 1432÷( 13×52+78)
7. 125×(33- 1) 8.37.4-(8.6+7.24-6.6)
Do the math. ( 1∶ 1)
( 1) 156× 107-7729 (2)37.85-(7.85+6.4)
(3)287×5+96990÷3 18 (4) 1554÷[(72-58)×3]
The application problem solution (urgent answer) in the next semester of grade three is definitely not suitable for the equation because it is the third semester of primary school. Here I introduce a method to solve the formula:
Assuming that the number of people participating in the performance increases by 9, there will be more first phalanx 12+9=2 1 person.
The number of people in the second phalanx is just neither more nor less. Because the second square matrix is added with one person in the horizontal and vertical directions, that is, 1 column and 1 row. If the column 1 is added first, which is equivalent to the original number of 1 teams, and the line 1 is added, the number of 1 teams is also increased, but this team needs more 1 people than the original one-to-one, so the original number of two teams is increased by 1 people. The total number of extra people is 2 1.
Originally, the number of people in each team was (21-1) ÷ 2 =10 (people).
So the original total number of people attending the performance is:10×/kloc-0+12 =112 (people).
What is the answer to "learning while playing" in the third semester? All of them?
The third day of the next semester oral math problem 360 ÷ 3 =
42× 20=
12 × 50=
1500-700=
5900-4000=
76 + 27=
840 ÷ 2=
770 ÷ 7=
30× 20=
40× 50=
9900+ 100=
700 ÷ 7=
240× 10=
390 ÷ 3=
60× 50=
7 1 - 22=
50 × 90=
14 × 20=
600+ 1200=
840 ÷ 4=
36 + 49=
10 × 60=
800 × 50=
180 ÷ 3=
120 ÷ 6 =
7500+500=
460+ 140=
33 × 20 =
990 ÷ 3 =
440 ÷ 4 =
83-57 =
860 ÷ 2=
1 100-600=
6900- 1900=
720 ÷ 8=
0÷999=
7 × 800=
23 × 30=
290 - 190=
690 ÷ 3=
690÷3×6=
17×40=
100-63=
3.2+ 1.68=
2.8×0.4=
14-7.4=
1.92÷0.04=
0.32×500=
0.65+4.35=
10-5.4=
4÷20=
3.5×200=
1.5-0.06=
0.75÷ 15=
0.4×0.8=
4×0.25=
0.36+ 1.54=
1.0 1×99=
420÷35=
25× 12=
135÷0.5=
3/4 + 1/4 =
2 + 4/9 =
3 - 2/3 =
3/4 - 1/2=
1/6 + 1/2 - 1/6 =
7.5-(2.5+3.8)=
7/8 + 3/8 =
3/ 10 + 1/5 =
4/5 - 7/ 10 =
2 - 1/6 - 1/3 =
0.5 1÷ 17=
32.8+ 19=
5.2÷ 1.3=
1.6×0.4=
4.9×0.7=
1÷5=
6÷ 12=
0.87-0.49=
24/3*9=
15*3-20=
12* 1 1+ 13=
25*4+36=
36+25- 14=
2*36+4=
12/4*35=
(23-8)*3=
14/2+2 1/3=
42/ 14+54/9=
55/ 1 1*20=
36/9* 12=
16/4* 19=
16-45/ 15+6=
70÷7=
20× 10=