Sprint at the end of the sixth term 100 points Unit 3 Application Questions 4, 5, Additional Questions Answers

1. solution: let a be x tons, then b be (8 10-x) tons.

x- 150/(8 10-x)- 150 = 10/7

7(x- 150)= 10(8 10-x- 10)

7x- 1050 = 8 100- 10x- 1500

7x=6600- 10x+ 1050

7x=7650- 10x

17x=7650

x=7650÷ 17

x=450

8 10-x

=8 10-450

= 360 A:A is 450 tons and B is 360 tons. ..

2.18 ÷1/3000000 = 54000000 (cm) = 540 (km)

540 ÷ 5 =108km

108(5+4)= 12 (km)

12÷(5-4)= 12(km) A: Speed difference 12km.

3. Solution: Assuming that B produces X, then A is 1/2x.

1/2x / 25=(x- 120) / 40

40× 1/2x=25(x- 120)

20x =25x - 3000

25x-20x=3000

5x=3000

x=3000÷5

X=600 A: B will produce 600 parts.