I think so, too. If you are wrong, don't call me. .

Because of one? -2ab+b？ =0, so (a-b)? =0, so a = B.

So the triangle OAB is an isosceles right triangle.

If you want to make an isosceles right angle △ADE with AE as the hypotenuse, only DE can be the center line of the triangle, then E is the midpoint of the line segment AB.

And because p is the midpoint of be, PD=PO.

Then, then, think to yourself. . .