Let PQ be x, then pn=2x.

The area of the big triangle =8*6* 1/2=24 (base times half the height).

The area of the big triangle is also equal to the area of the rectangle+the area of the other three small triangles.

Rectangular area = 2x * x = 2x 2

The area of triangular disk =2x*(6-x) 1/2.

Area of triangle PBQ and triangle MNC (another triangle) = 1/2 * (8-2x) * X

That is 2x2+x * (6-x) *1/2+1/2 * (8-2x) * x = 24.

That is, 10x=24.

x=2.4

The circumference of the rectangle is 6x= 14.4.

okay