Even deceleration after unloading: a2=△v△t=- 10m/s2.

According to Newton's second law: -(mgsin 37+ micron ·GCOS 37)= ma2.

Solution: μ=0.5

(2) The uniform acceleration process is obtained by Newton's second law: f-MGS is at 37- micron GCOS 37 = Ma 1.

Solution: F= 16N?

(3) Let the acceleration time be t 1 and the deceleration time be t2.

Maximum speed: vm=a 1t 1.

0 = a 1t 1+a2(T2-t 1)

The speed at 2.2s is 2.0m/s: Yes: 2.0=vm-a2(2.2-t 1).

SAC=v2(t 1+t2)

Simultaneous solution: SAC= 10.8m?

Answer: (1) The dynamic friction coefficient μ between the object and the inclined plane is 0.5;

(2) Constant force f is16n; ;

(3) The distance between AC is10.8m. 。