If gambling technology is not considered, then the probability of A and B winning is the same, that is, the winning rate of A and B is 0.5.

A lost the first game.

Then there are three gambling games left, and there are three games left.

1 probability. A loses three games: 0.5*0.5*0.5=0. 125, so A * * * loses four games.

The chip taken is 0.

2. The probability that A loses two games and wins 1 game is 0.5 * 0.5 * (1-0.5) = 0.125, so A*** loses three games and wins1game.

The chip taken is 0.

3. The probability that A loses 1 wins two games is: 0.5 * (1-0.5) (1-0.5) = 0.125, so A*** loses two games and wins two games, which is a draw.

This will take away half of the chips, which is 0.5* 1=0.5.

4. The probability that A loses 0 games and wins 3 games is (1-0.5) * (1-0.5) * (1-0.5) = 0.125.

So you can take all the chips, which is 1.

To sum up, the expectation that A can take away the chips is 0 * 0.125+0 * 0.125+0.5 * 0.1* 0.125 = 3/16.

In the end, A can take 3/ 16 of all chips, and B can take 13/ 16 of all chips.