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Time of second grade math application problems
4000 meters.

Change the distance after 2 minutes, and then discuss the walking situation after 2 minutes;

It takes him less time to complete the distance with 60 meters per minute instead of 50 meters: 5+8= 13 minutes;

Then the time to complete this distance at a speed of 50 meters per minute is: 60× 13÷(60-50)=78 minutes;

Therefore, the time to walk the whole course at a speed of 50 meters per minute: 78+2=80 minutes;

Distance: 80× 50 = 4000m.

Mathematics application problems and answers in senior two: distance problem

Party A and Party B walk in opposite directions from two places 800 meters apart at the same time. How many meters did they walk together when they were 200 meters apart?

Answer and analysis:

600 m or 1000 m.

When two people don't meet, when they are 200 meters apart: 800-200=600 (meters); When two people meet, when they are 200 meters apart, 800+200= 1000 (meters).

A: Two people walked 600 meters or 1000 meters together.