Solution: AF=BF (the distance between the point on the vertical line in the line segment and the two ends of the line segment is equal).

Delta perimeter of delta △BCF

=BF+FC+BC

=AF+FC+BC

=AC+BC

=AB+BC

= 16

∠ The antipodal angle of ∠EFC = 180-90-50=40.

∠EFC=40