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Mathematical addition and subtraction application problems
5X+3Y=7 ①

-5X+7Y=3 ②

①+② Obtain:

10Y= 10

Y= 1

Substitute Y= 1 into ① to get:

5X+3=7

5X=4

X=4/5

So X=4/5, Y= 1 is the solution of the equations. Note: You can check several generations to see if the result is correct.