(1) When these two sides are right angles (i.e. Figure 1), AC &；; sup2+BC & amp； sup2AB & ampsup2

5 & ampsup2+ 12 & amp； sup2AB & ampsup2

13x & amp； sup2AB & ampsup2

AB= 13

Equal area method:

5× 12= 13×h

60= 13h

60/ 13=h

h=60/ 13

Height of writing edge: hypotenuse = 60/13:13 = 60:169.

(2) When one of the two sides is a right-angled side and the other is a hypotenuse (as shown in Figure 2) (because the hypotenuse is longer than the right-angled side, the hypotenuse must be 12), AB &；; sup2-SC & amp； Sup2= BC & ampsup2

12。 sup2-5 & amp； Sup2= BC & ampsup2

144-25 = BC & amp； sup2

1 19。 sup2

BC= root number 1 19

Equal area method:

5× radical number 1 19= 12h.

Root number119 = 2.4h.

Root number119 ÷ 2.4 = h.

Height of hypotenuse: hypotenuse = root119 ÷ 2.4:12 = root19: 28.8 = 5× root1/kloc-0.