1) Empty four boxes, that is to say, put all 10 balls in one box: C (5, 1) = 5.

2) Empty three boxes c (5,2) * c (9, 1) = 10 * 9 = 90.

Empty three boxes and choose two boxes to put the ball: C(5, 2)

The possibility of putting the ball in two boxes, using the insertion method: C (9, 1)

The following reasons are the same as above

3) Empty 2 boxes and select 3 boxes to put the ball:

C(5，3)*C(9，2)= 10*36=360

4) Empty 1 box, and select 4 boxes to put the ball:

C(5，4)*C(9，3)=5*84=420

5) None of the five boxes are empty:

C(9，4)= 126

Total amplification method: 5+90+360+420+126 =1001.