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09 10 14 15, a quick answer to the science simulation of senior three in the entrance examination of three northeastern provinces.
In 2009, three schools in three northeastern provinces took the first mock exam.

Volume one multiple-choice questions

1.A 2。 C 3。 B 4。 C 5。 B 6。 C 7。 B 8。 A nine. D 10。 C 1 1。 A 12。 C 13。 B

14.C 15。 A 16。 B 17。 ACD 18。 19 BC. B 20。 BD 2 1。 advertisement

Volume 2 Non-multiple choice questions

22 I 0.590 2.642

2 points for each space, ***4 points.

ⅱ( 1)E; C

(2) Answer

(3) Connecting physical drawings

(4)① Enlarge ②10Ω

(1) 1 point (2)3 points per space (3)4 points (4) 2 points per space.

23.

(1) From the speed-time diagram of the small block sliding process: (3 points)

M/s2 ( 1)

The acceleration is 8.0m/s2 when the small piece rushes up the inclined plane.

(2) small objects are subjected to gravity, supporting force and friction, and a rectangular coordinate system is established along the inclined plane,

(2 points)

(2 points)

(2 points)

Replace the solution with data (2 points)

(3) Let the distance between the highest point that the object block can reach when it rushes onto the inclined plane and the bottom end of the inclined plane be s,

Upward movement stage (3 points)

( 1)

24. Solution: The car moves in a circle with a radius of R. When it is at the highest point of the circular orbit, the sum of the gravity of the car and people provides centripetal force. Let the speed of the car when it slides to point D be U. According to Newton's second law,

(4 points)

Get u= 10 m/s (2 points)

Let people and cars move from the horizontal plane to D at the same speed V, and the mechanical energy is conserved, which is obtained according to the law of conservation of mechanical energy.

(4 points)

V= 15m/s (2 points)

When people contact the car and make it move forward with people, there is no external force in the horizontal direction, so the momentum in the horizontal direction is conserved.

(4 points)

V0 = 20m m/s (3 points)

25.( 1) protons do uniform circular motion after being injected into a magnetic field, including

EvB=mv2/r (3 points)

Get v=eBr/m (1 point).

(2) Protons are injected with a magnetic field along the positive direction of the X axis, and enter the electric field at a speed V perpendicular to the direction of the electric field after passing through the arc of 1/4, with a period of

(2 points)

Time to move in a magnetic field

T 1=T/4=πm/2eB (2 points)

Do parabolic motion after entering the electric field and move along the electric field direction to reach the Y axis, so there is

(2 points)

T2= (2 points)

The required time is t= t 1+ t2= (2 points).

(3) After the proton turns the angle of120 in the magnetic field, it enters the electric field from the vertical electric field line at point P, as shown in the figure.

Distance between point p and y axis

X1= r+rsin30 =1.5r (2 points)

So the time required for protons to enter the electric field and reach the Y axis is = (2 minutes).

Protons do uniform linear motion along the Y axis in the electric field, so there are

(2 points)

The coordinate of the position where the proton reaches the Y axis is (0, r+) (2 points).

Figure (2 points)

26.( 10) (1)N2 (2 points)

(2) (2 points, if you fill in the correct CO electronic type, you will also get extra points)

(3) Ionic bonds and nonpolar bonds. (2 points, the second empty answer * * * price key also gives points) ②④ (2 points, all correct answers give points)

(4) CS2+2H2CO2+2H2S (2 points)

27.( 18)( 1)Al+4oh-3e-= alo 2-+2h2o(3)

(2)10-2–10-12 mol/l, or c (oh-)–c (h+) (2 points)

(3) No (1); Because the chloride of A has a low melting point, it is judged that its crystal is a molecular crystal, which is not ionized in the molten state and cannot be electrolyzed (2 points).

(4)4NH3+5O2 4NO+6H2O (conditional error 2 points, 1 min)

(5) ① Al3++3HCO3-= Al (OH) 3 ↓+3CO2 ↑ (2 points, 1 minute without ↓ and ↑)

(2) Alum or Alum (1); 1 mol/l (3 points)

28.( 15) (1) Absorb the water produced by the reaction, reduce the product concentration, and move the balance forward. (2 points)

(2)a and B (2 points per grid, 1 minute)

(3)①②③ (2 points, the answer is completely correct)

(4)

(3 points, condition error deduction 1 point)

(5) (2 points)

(6)80% (2 points) 123 (2 points, the answer is completely correct)

29.( 17) ( 1)①

(2 points) Substitution reaction (1 minute, hydrolysis reaction should be given)

Conclusion of reagent phenomenon used in step

1 FeCl3 _ 3 solution is purple, m.

The colorless gas in 2 NaHCO3 solution is e; The other substance is n.

three

four

(7 points, each of the first five spaces is 1 minute, and each of the last two conclusions is 1 minute. All other reasonable answers to this question are given points)

(2)

(4 points, 2 points each, and other reasonable answers are also given)

(3)①NaHCO3 ②NaOH or Na2CO3 ③ Na (3 points, each 1 min)

30.(24 points)

I. (10)

(1) Newly established synapse (2 points); Synapses take longer to establish (2 points). (2) Two-way (2 points) (3) Quiet (2 points); Respiratory function (2 points).

Two. (14)

(1) light (1) and temperature (1); In summer, all water layers have strong biological respiration (2 points).

(2) There are almost no plants in the sediment (1), but there are a lot of aerobic organisms living in it (1).

(3)① Thermocline (or measured water layer or sampled water layer) (2 points);

② Respiratory dose (or respiratory oxygen consumption) (2 points); Net photosynthesis (or oxygen accumulation in photosynthesis) (2 points);

A+b(2 points) (correct wording is acceptable).

3 1.( 18 points)

(1)(4 points)

P AAbb × aaBB

Many knots are short and few knots are long.

F 1 AaBb

Multistage length

F 1 generation has genes A and B, which are characterized by many nodes and long nodes, so it is higher.

(2)(4 points)

p ala 1×a2a 2

Rust resistance, rust resistance.

F 1 AlA2

Two-rust resistant

F 1 AlA2 has two rust resistance genes, which can resist two kinds of rust.

(3)①AAbb(2 points), AaBb(2 points) and AaBb(2 points);

② 1: 4: 6: 4: 1 (4 points).