∴∠ 1=∠2(∠abd=∠2,∠bad=∠ 1)

AB = AC = CD

∴∠2=∠3(∠3=∠ACB)

∴∠4=∠5

Mark ∠4 as ∠DAC.

∵∠2+∠3+(∠ 1+∠4)= 180

And ≈5(≈ADC) is the exterior angle of △ABD =∠2+∠3.

∴∠ 2+∠ 3+∠ 1+∠ 2 = 180 (because all three angles are equal).

∴∠ 1=36

∴∠5=36+36=72

∴∠4=72

∴∠BAC=∠4+∠ 1= 108