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Synchronous learning and exploration in the new classroom of Qingdao edition of mathematics; the answer to the first small question on page 82, question 6 of the sixth grade.
1. Let length =X and width = y, then (X+80)*(Y+8)=X*Y+208, and find 2(X+Y)=?
2. Solve the equation (X+80)*(Y+8)=X*Y+208 and get X*Y+8X+8Y+64=X*Y+208, and get 8(X+Y)=208-64.