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Mathematical alarm clock
According to the meaning of the question, the hour hand and the minute hand must coincide at that time, so we only need to find out that the time when the hour hand and the minute hand overlap is between 7 o'clock and 8 o'clock.

Let the hour hand and minute hand overlap at 7: 00 x. Because the speed of the hour hand is112 of the minute hand speed, from 7 o'clock sharp to 7 o'clock x minutes, the minute hand turns to x squares, then the hour hand turns to x/ 12 squares, and the minute hand turns 35 squares more than the hour hand. According to the meaning of the question:

x-x/ 12=35

Solution:

X=38 and 165438+2/0.

So the time was 7: 38, 1 1: 2.