The Mid-Autumn Festival is coming, and Xiaoming's father wants to help sell zongzi with his life. Thirdly, he bought a gift package of 100 yuan for each customer. Xiao Ming's father said: "The price is reduced today, and we can sell it for 250 yuan! You return the 50 yuan to others. " Xiao Ming spent money on shopping in 20 yuan, and later everyone paid back 10 yuan. In this way, everyone handed in 90 yuan: 90*3=270 yuan, 270+20=290 (plus 20 yuan used by Xiaoming). So,1where is 0 yuan?

Solution: In fact, the money they paid should include the money used by Xiao Ming, so the algorithm of the topic is wrong. Correct solution: 270-20=250 (yuan) This 250 yuan is the amount of money that Xiaoming's father collected.

2. A shop sells zongzi. There are 1.760 zongzi stuffed with bean paste and candied dates, 60% of zongzi stuffed with bean paste and 5 1.4 zongzi stuffed with candied dates, so the number of zongzi left in the two fillings is exactly equal. If 4 yuan buys a rice dumpling stuffed with bean paste, the price is 5 yuan; A jiaozi stuffed with candied dates bought in 4.5 yuan and sold in 5 yuan. So how much profit can the merchants make after all these jiaozi are sold out?

Thinking of solving the problem: this problem is profitable, so it is the key to find out the number of all kinds of zongzi. The correct solution: suppose there are x zongzi stuffed with bean paste in the store (0.4x= 1760-x-5 14). The solution is: x=890, so there are (1760-890)780 zongzi stuffed with candied dates. Profit = (selling price-buying price) * number of candied dates sold