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1, if 1+2+3+…+n=a, find the algebraic expression (x to the nth power Y)(n-65438+X to the 0th power Y)(X to the nth power Y)…(n-65438+X to the 0th power y).

Solve the original formula = x (1+2+3+…+n) * y (1+2+3+…+n) for power * for power sign.

=x^a * y^a

2. It is known that 10' s 25× 2× n power m power = 2' s 5× 4 power 7 power. Find m, n

The m power of the solution is 25× 2× 10 n =5 (2m+n) power +2 (n+ 1) power.

That is, n+ 1=4 2m+n=7 n=3 m=2.

3. It is known that the power a of 10 = the power b of 310 = the power c of 510 =7. Try to write 105 as a power of 10.

Solution 3×5×7= 105. Obviously, 10 (A+B+C) is what you want.

4. Given 9' s n+ 1 power -3' s 2n power =72, find the value of n..

Solution 8× 3 (2n) = 72n = 1.

5 、-3x 、-2

6、4xy

7,[(x^2-2x+5)-(x^2-2x-3)]^2=64

8,(A+B)/2 、( A-B)/4