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Let's help solve a math problem.
The speed ratio is 4: 3.

Let the original velocity of A be 4x and the original velocity of B be 3x.

Because the speed ratio is 4: 3.

So the ratio of distance when meeting is 4: 3.

So the distance ratio from the venue to destinations A and B is 3: 4.

So the speed ratio after A and B meet is 3: 4.

B it's 35 faster than before.

So 4x:(3x+35)=3:4.

4×4 = 3×(3x+35)

16x=9x+ 105

7x= 105

x= 105÷7= 15

So A travels 4x = 60km per hour.