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20 16 xiangfang Moore's mathematical answer
It is proved that (1) when DP∑AC intersects BC at point P,

∫DP∨AC,DF∨BC,

∴ Quadrilateral FDPC is a parallelogram,

∴FC=DP,∠C=∠DPH,

∫∠BAH =∠C,

∴∠DPH=∠ABD,

* in △ Abd and △PBD

∠ Budd =∠BPD∠ABD=∠PBDBD=BD

∴△ABD≌△PBD(AAS),

∴AD=DP,

DP = FC。

DF = 539GC,

Proof: BD = BH,

∴∠BDH=∠BHD,

∠∠BDH =∠ Abd +∠ Budd, ∠ Beya =∠EBC+∠BCA, ∠ Abd =∠EBC, ∠ Budd =∠BCA,

∴∠aed=∠bdh=∠bhd=∠ade,∠abd=∠hac=∠dbh,

∴AD=AE,

∫DF∨BC,

∴∠EDF=∠EBC=∠DAE,

∫∠DFE =∠DFE,

∴△FDE∽△FAD,

∴DF2=EF? AF, dead =EFDF,

Let AE=2a, EF=a,

∴AD=FC=2a,DF2=a? (2a+a)=3a2

∴DF=3a,

∴DE2a=a3a

∴DE=233a,

∫DF∨BC,

∴ DFBC = I have praised it and stepped on it. What is your evaluation of this answer? Put away comments//high quality or satisfaction or special types or recommended answers dottimewindow.iperformance & window.iperformance.mark ('c _ best',+newdate); Lawyer recommendation service: If your problem has not been solved, please describe your problem in detail and provide free professional consultation through Baidu Law Professional Edition. Other similar questions 2017-10-03 (2014? As shown in the figure, in Rt△ABC, ∠ C = 90, D is a point on AB, and DE⊥BC is in E, connecting AE, if BE=AC, BD=25, DE172016-16550. Suihua) As shown in the figure, in the rectangular ABCD, the bisector of AD=2AB, ∠BAD intersects BC at point E, and DH⊥AE intersects H, connecting BH and extending the intersection of CD at point 722018-03-05 (2014 Harbin). The e point is in BC172011-05-zhong 232011-05-21In the rectangular ABCD, the h point is on the diagonal BD, and HC is perpendicular to BD, at the intersection of HC extension lines. 4520 12-07-05 as shown in the figure, in the rectangular ABCD, H point is on the diagonal BD, HC is perpendicular to BD, and the bisector of the intersection angle of the extension line of HC is at E point, indicating that CE and BD are 2792011-05-13 as shown in the figure. H point. bisector of intersection point, which shows that the quantitative relationship between CE and BD 752020-03-30ABCD is rhombic diagonal AC, BD intersects at O point, and DH ⊥AB and H are connected. OH proof ∠DHO=∠DCO. & gt recommended for you: F.context('cmsRight', [{'URL':'/d01373f082025aaf511aa256e9edab64034f1a07? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto ',' contractId':'A24KA00562 ',},{ ' URL ':/s? word = % E6 % AC % A7 % E6 % B4 % B2 % E6 % 9D % AF & sa = searchpromo _ ozb _ zhidao _ tuijian ',' src ':'/3 BF 33 a 87 e 950352 AAF 5 df 4954 143 fbf2b 2 1 18 b6b? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto ',' contractId ':' ',}]); The price of electric cars has dropped many times. Is the quality guaranteed? What impact will the "network toilet" have? Is Huaqiang North's second-hand mobile phone reliable? Why is the cost of cancer treatment getting higher and higher? I recommend f.context ('recbrand', [{"img": "\/86D6277F9E2F07083523F69DFB 24B 899A901F20d? x-BCE-process = image % 2f resize % 2Cm _ lfit % 2Cw _ 450% 2Ch _ 600% 2c limit _ 1% 2f quality % 2Cq _ 85% 2f format % 2Cf _ auto "," url":"/hm.js? 6859 ce 5a af 00 FB 00387 e 6434 E4 FCC 925 "; var s = document . getelementsbytagname(" script ")[0]; s.parentNode.insertBefore(hm,s); })(); window . TT = 1720 1354 16;