How to formulate mathematics? This formula only applies to equations. The formula is to add or subtract a number on the left and right sides of the equation at the same time, so that the formula on the left side of the equation becomes a completely flat expansion, and then the equation can be factorized and solved. That is, the matching method is based on the complete square formula: (a+ or -b) square =a square+or -2ab square.
For example, if the formula you are talking about is not an equation, it cannot be solved by matching method. Let me give you an example:
2a？ -4a+2=0
Answer? -2a+ 1=0 (the quadratic coefficient should be changed to 1 first, so it is convenient to solve the problem by collocation method, so the quadratic coefficient 2 is divided by both sides of the equation).
(a- 1)？ =0 (the formula in the previous step found that the left side is completely flat, so according to the complete square formula, a? -2a+ 1 factorization is (a- 1)? Thereby completing the formula)
A- 1=0 (both sides of the final equation are squared at the same time)
A= 1 (result obtained)
I have made it very clear, I hope you can understand.
How to formulate mathematics! Do you mean the formula when solving the equation?
There are several steps:
1, and the coefficient of quadratic term is 1.
Step 2 move the project
3, formula (plus half square coefficient on both sides)
4. Prescription
I wish you happiness.
How to formulate "matching method" in mathematics? In basic algebra, collocation method is a method for transforming quadratic polynomial into the sum of the square of linear polynomial and constant. This method converts the polynomial in the following form into the coefficients A, B, C, D and E in the above expression, which can also be expressions and contain variables other than X. Matching method is usually used to derive the root formula of quadratic equation: our purpose is to turn the left side of the equation into a complete square. Because the complete square in the question has (x? +? y)2？ =? x2？ + 2xy？ +? Y2 form, you can deduce 2xy? = (b/a)x, so y? =? B/2a. Add y2 on both sides of the equation? = (b/2a)2, we can get:
This expression is called the root formula of quadratic equation.
solve an equation
In the unary quadratic equation, the matching method is actually to shift the terms of the unary quadratic equation and add the square of half the absolute value of the coefficient of the first term to both sides of the equal sign.
Example solution equation: 2x? +6x+6=4
Analysis: the original equation can be arranged as: x? +3x+3=2, which can be obtained by the formula (x+ 1.5)? = 1.25 can be solved by finding the root.
Solution: 2x? +6x+6=4
& lt= & gt(x+ 1.5)？ = 1.25
X+1.5 = the square root of 65438 +0.25.
How to make a mathematical formula = a [x+(b/2a)] 2+[(4ac-b 2)/4a]
Is the vertex in a quadratic equation of one variable ~
How to formulate in mathematics? Y = x2-6x-3 = x2-2 * 3x+32-32-3 = (x-3) 2-12 plus half the square of the first-order coefficient, and then subtract half the square of the first-order coefficient.
That's what our teacher said ~
How to learn mathematical matching method is a method in junior high school, but it is widely used in senior high school.
Look at a question and understand its meaning:
5X？ +2X-3=0？
1. Do X? There was no coefficient before: x? +2X/5-3/5=0
2. decompose the coefficient before x into a factor of 2: x? +2*( 1/5)X-3/5=0
3. add one and subtract one: x? +2*( 1/5)X+( 1/5)？ -( 1/5)? -3/5=0
4. Add the last two to the first three formulas: (X+ 1/5)? - 16/25=0
5. Move: (X+ 1/5)? = 16/25
6. solution: x+ 1/5 = 4/5 or x+ 1/5 =-4/5.
7. Re-solution: X=3/5 or X=- 1.
Among them, steps 1, 2 and 3 are the most critical! Understanding this method is much more useful than formula method. When I was in high school, I used the collocation method to solve a quadratic equation or inequality, so I should remember it.
How do the mathematical formulas match? For example, x 2-2x+4 = 0.
(x^2-2x+ 1^2)- 1^2+4=0
(X-2)^2+3=0
This equation has no solution.
Note: (2/2) 2 = 1 2, because the extra+is 1 2, it should be subtracted later.
How to match ax with mathematical matching method? +bx+c=0
x？ +bx/a+c/a=0
x？ +bx/a+(b/2a)？ -B? /4a？ +c/a=0
(x+b/2a)？ -(b？ /4a？ -4ac/4a？ )=0
(x+b/2a)？ =(b？ -4ac)/4a？
x+b/2a= √(b？ -4ac)/2a
x=-b/2a √(b？ -4ac)/2a
Then these two roots are: x = [-b √ (b? -4ac)]/(2a)
x 1=[-b+√(b？ -4ac)]/(2a)
x2=[-b-√(b？ -4ac)]/(2a)
When b? -4ac & gt； 0, with two different real roots,
When b? There are two equal real roots when -4ac=0,
When b? -4ac & lt； 0, with a pair of * * * yokes.
Mathematical formula. The formula of the equation is to add half the square of the first term coefficient on both sides of the equation, while the function is to add half the square of the first term coefficient and then subtract half the square of the first term coefficient.
For any a and b (where a and b can refer to any formula, including transcendental and algebraic expressions), there are both.
,
Generally speaking, the former formula is best used for x? y？ Formula, the latter formula is best used for x? Formula Ax)
For any a, b, c, there are
Generally speaking, this formula is best used for x? +y？ +z？ Formulate)
When formulating, you only need to specify two or three items to apply the above formula.